Need to know
Real Analysis
Lebesgue
Integration
Definition 1. A characteristic
function or indicator function of a set
is defined as
Definition 2. A simple function is
a function which takes finitely many values. Thus for any simple
function there is a set of values
and a collection of sets
such that
Definition 3 (Lebesgue Integration). Suppose
a simple function such that
and
is a measure on
.
We define
For a non-negative measureable function
,
we define
Proposition 1 (integration over a set and useful
consequences). We define
.
Note that any characteristic function is a simple function and so for
any
with
we find
Theorem 2. If
is Riemann integrable, then
is Lebesgue integrable and the integrals agree.
Standard Limit
Theorems
Theorem 3 (Lebesgue’s Monotone Convergence Theorem).
Suppose
is a measure space and
is a family of real-valued measurable functions with
for all
and
for all
.
Then
Theorem 4 (Fatou’s Lemma). Suppose
is a measure space and
is a family of real-valued nonnegative measurable functions. Then
Theorem 5. (Dominated Convergence
Theorem)Suppose
is a measure space and
is a family of measurable real-valued functions where
pointwise. If there exists a non-negative integrable function
such that
for all
for each
.
Then
Differentiation
Definition 4 (Absolutely Continuous). Let
be a measurable space and let
be measures on
.
If
for all
,
then we say
is absolutely continuous with respect to
,
denoted
.
Theorem 6 (Radon-Nikodym). Suppose
are measures on a
-algebra
such that
is a
-finite
positive measure and
a finite positive measure with
.
Then there exists a
-integrable
function
measurable with respect to
such that
unique up to almost everywhere equivalence.
Other
Theorem 7 (Hölder’s inequality). For functions
and
such that
then
Lemma 9 (Chebyshev’s Inequality). If
,
then
Theorem 10 (Egorov’s Theorem). Suppose
is a finite measure,
,
and
almost everywhere. There exists a measureable set
such that
and
uniformly on
Complex
Theorem 11 (Liouville’s Theorem). If
is an entire function and there exists a
such that
for all
then
is constant
Theorem 12 (Morera’s Theorem). A function
is holomorphic on
if and only if
for any triangle
contained by
.
Theorem 13. For a function
and a closed, piecewise
curve
Theorem 14 (Riemann Mapping Theorem). Every
simply connected open subset of
is conformally equivalent to the open unit disk.
Theorem 15 (Riemann’s Removable Singularity
Theorem). Suppose a function
has an isolated singularity at
.
There exists a
and a
such that
for all
if and only if
is a removable singularity
Proposition 16 (Cauchy’s Estimates). Suppose
.
If there exists a
such that
in a disk
,
then
for
Problems and
Solutions
Real analysis
Question 1. Define
by
and
.
Show that for every
,
there is an open neighborhood
of
with
,
on which
is injective, and there is a differentiable
such that
for all
Answer 1. Set
and
so that
.
(Scratch: Taking all of the first order partial derivatives
,
,
and
)
. For all
,
the determinant of the Jacobian of
at
is
.
Given any
,
since
by construction and
for any
,
.
Therefore, the Inverse Function Theorem states that there is such a
neighborhood
of
and such a function
.
0◻
Question 2. For
and
define
Show that
is a continuous function of
.
Question 3. Let
be a measure space and
.
Show that, for all
,
there is a
so that, for all
,
Answer 2. Since
,
it must be the case
a non-negative measurable functions. Thus, there is a sequence of
non-negative simple functions bounded above by
and converging to
pointwise. Given
we can choose some simple function
such that
.
Question 4. Let
be a measure space. A family
of measurable functions is said to be uniformly integrable if, for every
,
there is a
so that, for all
and
Show that any finite
is uniformly integrable. (You may ignore
)
4. Let
be the unit disc. Either construct a holomorphic function
with
and
or prove that one does not exist.
5. Set
and
.
Give an explicit conformal equivalence
.